Question

construct a triangle abc with sides 3cm,4cm and 5cm. now construct another triangle whose sides are 4/5 times corresponding sides of ∆ abc?​

Answer 1

Step-by-step explanation:

Draw a triangle ABC with BC=6cm, AB=5cm and ∠ABC =60

o

. Then construct a triangle whose sides are

4

3

of the corresponding sides of the Δ ABC.

Step 2: Draw a ray BX making an acute angle with BC on the opposite side of vertex A.

Step 3: Locate 4 points, B

1

,B

2

,B

3

,B

4

on line segment BX.

Step 4: Join B

4

C and draw a line through B

3

, parallel to B

4

C intersecting BC at C

′

.

Step 5: Draw a line through C

′

parallel to AC intersecting AB at A

′

.

The triangle A

′

BC

′

is the required triangle.