Question

construct a triangle pqr in which PQ = 4 cm and QR = 6 CM angle pqr =70 degrees construct triangle triangle such that each side of a triangle is 3 by 4 of triangle pqr​

Answer 1

Step-by-step explanation:

• first draw a rough figure
• draw a line segment QR of 6cm
• draw a angle of 70° using a protractor
• mark point P on the line
• draw a line from point P to point R

Answer 2

P'QR' is the required triangle

Step-by-step explanation:

• draw  a base QR = 6 cm
• with Q as a center, make an angle of 70 degree
• with Q as a center and radius = 4  cm draw an arc
• join PR
• PQR is the original triangle
• below QR , make an acute angle RQX
• along QX mark four points $Q_1,Q_2,Q_3,Q_4$ on equal distances
• join $Q_4R$
• from Q3  , draw  $Q_3R'||Q_4R$
• From R' draw $R'P' ||RP$

P'QR' is the required triangle

#Learn more :

Construct a triangle pqr with QR is equal to 6 CM PQ is equal to 4 cm and angle pqr is equal to 60 degree construct another triangle P'Q'R' similar to triangle PQR with side QR'=4/3ofQR​

https://brainly.in/question/14663781