Construct a triangle PQR in which PQ = 5.8 cm, QR = 6.5 cm, PR = 4.5 cm.
Answers
Answered by
12
Construct a triangle PQR in which PQ = 5.8 cm, QR = 6.5 cm, PR = 4.5 cm.
Steps of the Construction:
- Draw the line QR of 6.5 cm.
- From the point, Q draw an arc at 5.8 cm.
- Now from the point R draw and another arc which cut the previous arc at P.
- Now join the points PQ and PR.
The figure we get is the required triangle PQR.
For the figure refer to the attached image.
Attachments:
Answered by
5
Answer:
Steps of Construction:
(i) Construct a line segment PR = 6.5 cm.
(ii) Taking P as centre and 4.5 cm radius and R as centre and 6 cm radius construct arcs which intersect each other at Q.
(iii) Now join PQ and QR.
(iv) Taking P as centre and 5 cm radius and R as centre and 5.5 cm radius, construct arcs which intersect each other at S.
(v) Join PS and SR.
Hence, PQRS is the required quadrilateral.
Attachments:
Similar questions
Hindi,
4 months ago
CBSE BOARD X,
4 months ago
English,
4 months ago
Math,
9 months ago
Business Studies,
9 months ago
Math,
1 year ago