Math, asked by shreyanshvaibhav12, 4 months ago

Construct a triangle PQR in which QR=5cm angle Q=70° and angle R= 50° .​

Answers

Answered by Margeekkhatri
17

Construct a triangle PQR in which QR=7cm,∠Q=75

and PQ+PR=13cm

ANSWER

1.Draw base BC=7cm

2.Let's draw ∠B=75

.Let the ray be BX

3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D

4.Join $$CD$

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:△ABC is the required triangle.

solution

I hope this answer helps you

Answered by goswamisunita509
9

Answer:

1.Draw base BC=7cm

2.Let's draw ∠B=75

.Let the ray be BX

3.Open the compass to length AB+AC=13cm.From point B as center, cut an arc on ray BX.Let the arc intersect BX at D

4.Join $$CD$

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:△ABC is the required triangle.

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