Question

factorise: 4a (a+b)^2 - 25 (a+b)^2​

Answer 1

Answer:

$4</p><p></p><p>3</p><p>+</p><p>4</p><p></p><p></p><p>2</p><p>+</p><p>8</p><p></p><p></p><p>2</p><p>−</p><p>2</p><p>5</p><p></p><p>2</p><p>−</p><p>5</p><p>0</p><p></p><p></p><p>−</p><p>2</p><p>5</p><p></p><p>2$

HOPE THIS HELPS....

Answer 2

Answer:

$4a ({a + b)}^{2} - 25 {(a + b)}^{2} \\ {(a + b)}^{2} \: is \: common \: in \: both ,\: so ,\: will \: take \: it \: common. \\ = {(a + b)}^{2}(4a - 25) \\now \: we \: can \: write, \\ = {(a + b)}^{2}( ({2a)}^{2} - {5}^{2} ) \\by \: using \: formula \: ( {a}^{2} - {b}^{2} ) = (a + b)(a - b) \\ = {(a + b)}^{2}(2a + 5)(2a - 5)$