Math, asked by triangleabc, 1 year ago

construct a triangle PQR in which QR = 6 cm. angle PQR = 100 degree and angle QRP = 45 degree.

Answers

Answered by Poorvanshi31
0
steps of construction: 1.draw a line segment QR=6cm.
2. at Q draw an angle of 100 degree using protactor and extend the ray.
3. At R draw 45 degree angle with compass bisecting 90 degree angle. Extend the ray
4. the point of intersection of both the extended rays will be named as P.
5. PQR is required triangle

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