Find the value of k if the point (4,3) is a solution of the equation 3x-ky=k+2. Check whether (-2,-6) lies on the same line.
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the point (4,3) is solution
so,
x=4 & y=3
putting these in equation,
3x-ky+2=k+2
3×4-k×3=k+2
12-3k=k+2
12-2=k+3k
10=4k
10/4=k
5/2=k
now the point (-2,-6)
where,x=-2 & y=-6
putting them in equation,
3x-5/2y=5/2+2
(6x-5y)/2=(5+4)/2
6x-5y=9
now taking LHS,
6×(-2)-5×(-6)
-12+30
18....
since,LHS≠RHS
so, these points (-2,-6) will not lie on the same line!!
so,
x=4 & y=3
putting these in equation,
3x-ky+2=k+2
3×4-k×3=k+2
12-3k=k+2
12-2=k+3k
10=4k
10/4=k
5/2=k
now the point (-2,-6)
where,x=-2 & y=-6
putting them in equation,
3x-5/2y=5/2+2
(6x-5y)/2=(5+4)/2
6x-5y=9
now taking LHS,
6×(-2)-5×(-6)
-12+30
18....
since,LHS≠RHS
so, these points (-2,-6) will not lie on the same line!!
kriyanshi1:
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