Question

construct a triangle whose perimeter is 13cm and ratio of the 3 sides is 2:3:4

Answer 1

ven ratio of sides = AB:BC:AC = 2: 3: 4let the divisor for all the dividend(the sides) be x.=> the ratio = 2x: 3x: 4xlet the triangle be ABCperimeter of triangle ABC = 13.5cm=> AB+BC+AC = 13.5 cm=> 2x+ 3x+ 4x+ = 13.5 cm=> 9x = 13.5cm=> x= 1.5cmtherefore sides of the triangle ABC are AB= 2x= 3 cmBC = 3x = 4.5cm& AC= 4x = 6cmnow,STEPS OF CONSTRUCTION1. Draw a line segment AB= 3 cm2. taking A as centre draw an arc by taking radius = 4.5cm3. now taking B as centre draw an arc by taking radius = 6 cm. Intersecting the previous arc at C.4. Join AC and BC.I hope this answer is helpful to you

Answer 2

given ratio of sides = AB:BC:AC = 2: 3: 4
let the divisor for all the dividend(the sides) be x.
=> the ratio = 2x: 3x: 4x
let the triangle be ABC
perimeter of triangle ABC = 13cm
=> AB+BC+AC = 13cm
=> 2x+ 3x+ 4x+ = 13cm
=> 9x = 13cm
=> x= 13/9cm
therefore sides of the triangle ABC are 
AB= 2x= 26/9cm
BC = 3x = 39/9cm
& AC= 4x = 52/9cm
now,

STEPS OF CONSTRUCTION
1. Draw a line segment AB= 26/9cm
2. taking A as centre draw an arc by taking radius = 39/9cm
3. now taking B as centre draw an arc by taking radius = 52/9cm. Intersecting the previous arc at C.
4. Join AC and BC.