Math, asked by LakshaySharma11, 1 year ago

In a given figure AD=BD=CD.Then prove that BAC is right angle.

Better if you solve and send picture!!

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Answered by hardiksharmah10
27
In the figure, AD = BD (Given)

Therefore, angle DAB = angle DBA = x (Say)

Also, CD = AD (Given)

Therefore, angle DCA = angle DAC = y (Say)

From angle sum property, angle DBA + angle DCA + angle CAB = 180 deg.

But angle CAB = angle DAB + angle DAC

angle DBA + angle DCA + angle DAB + angle DAC = 180 deg.

Therefore x + y + x + y =180 deg.

2 (x+y) = 180 deg.

x+y = 90 deg.

But x+y =  angle DAB + angle DAC = angle CAB = 90 deg.

Therefore triangle ABC is a right angle triangle.







LakshaySharma11: We need to prove angle BAC right angle...not the whole ∆
LakshaySharma11: ;((
LakshaySharma11: We need to prove angle BAC right angle...not the whole ∆
LakshaySharma11: We need to prove angle BAC right angle...not the whole ∆
LakshaySharma11: ;((
LakshaySharma11: We need to prove angle BAC right angle...not the whole ∆
hardiksharmah10: Thats what I proved
hardiksharmah10: BAC = ABC
hardiksharmah10: We can only prove that by this method
LakshaySharma11: thanks!!
Answered by rani107
16
hope it will help you
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