Question

construct an isosceles triangle whose base is 6 cm and whose Vertical angle is 72 degree

Answer 1

Answer:

Let consider an isosceles triangle ABC,

It is given that, base is 6 cm and whose Vertical angle is 72 degree

Let vertical angle be A = 72 and base BC = 6cm

Base angles, <B and <C are equal

Therefore sum of base angle = 180 - 72 = 108

<B = <C = 108/2 = 54°

Construction of triangle ABC

Step 1: Draw a line segment say BC = 6cm

Step 2: From B draw line BX making angle 54° with BC

Step 3: From C draw line CY making angle 54° with BC

Step 4: Mark the point of intersection of BX and CY as A

So triangle ABC is an isosceles triangle whose base is 6 cm and whose Vertical angle is 72 degree

Answer 2

Answer:

Let consider an isosceles triangle ABC,

It is given that, base is 6 cm and whose Vertical angle is 72 degree

Let vertical angle be A = 72 and base BC = 6cm

Base angles, <B and <C are equal

Therefore sum of base angle = 180 - 72 = 108

<B = <C = 108/2 = 54°

Construction of triangle ABC

Step 1: Draw a line segment say BC = 6cm

Step 2: From B draw line BX making angle 54° with BC

Step 3: From C draw line CY making angle 54° with BC

Step 4: Mark the point of intersection of BX and CY as A

So triangle ABC is an isosceles triangle whose base is 6 cm and whose Vertical angle is 72 degree

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