Construct ΔPQR, in which QR=4.2 cm, m∠Q=40° and PQ+PR=8.5 cm
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We have to construct the ΔPQR in which QR = 4.2 cm
And
PQ + PR = 8.5 Cm
Angle Q = 40°
We know that
Perimeter of triangle = sum of all sides = PQ + PR + QR = 8.5 + 4.2 = 12.7 cm
So
We make a triangle with such measurements by first making
the line QR = 4.2 cm
And Angle Q = 40°
Then we make the PQ of length = 5.17 cm and PR of length = 3.33 cm
And
Note that
5.17 + 3.33 + 4.2 = 12.7
That is
PQ + PR = 8.5 cm
Which is the required condition
See the graph of triangle ΔPQR in the figure below.
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