Question

construct the probability distribution or the probability mass function of the random variable y in number 1. please help​

Answer 1

Step-by-step explanation:

As we know that

∑P

i

=1

∴k+2k+3k+4k+5k=1

⇒k=

15

1

Thus the value of k is

15

1

X=x

i

P(X=x

i

) XP X

2

P

1 k k k

2 2k 4k 8k

3 3k 9k 27k

4 4k 16k 64k

5 5k 25k 125k

∑XP=55k=55×

15

1

=3.66 ∑X

2

P=225k225×

15

1

=15

Mean of the given data (

x

ˉ

)=∑XP=3.66

Variance of the given data =∑X

2

P−

x

ˉ

2

=15−(3.66)

2

=15−13.4=1.6

Hence the mean and variance of the given data is 3.66 and 1.6 respectively.