Question

Construct the trianglepqr in which pq =5.5cm ,qr=6.5 cm,rp=5cm

Answer 1

hey here is ur ans ....

• Draw PQ = 5.5 cm
• taking P as centre and measure 5cm , cut an arc .
• taking Q as centre and measure 6.5 cm , cut an arc name the point meeting as R .
• PQR is the required triangle .

hope this will help uh ...
nd plz mark as brainliest ...

Answer 2

ΔPQR  is constructed in  which pq =5.5cm ,qr=6.5 cm,rp=5cm

Step-by-step explanation:

Step 1 : Draw  a line segment PQ = 5. 5cm using ruler

Step 2 : Taking compass width = 6.5 cm and taking Q as center draw an arc

Step 3 : Taking compass width = 5 cm & taking P as center draw an arc such that it intersects arc drawn in step 2 at R

Step 4 : Join PR & QR

ΔPQR  is constructed in  which pq =5.5cm ,qr=6.5 cm,rp=5cm

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