Please help this please................
Answers
Answer:
It wont divide the polynomial
Step-by-step explanation:
Given, f(x) = 2x² - 3x + 5, g(x) = 2x - 3.
Long Division Method:
2x - 3) 2x² - 3x + 5 (x
2x² - 3x
----------------
5.
Therefore, remainder is 5.
Remainder Theorem:
it states that if you divide a polynomial f(x) by (x - h) then remainder is f(h).
=> 2x - 3 = 0
=> 2x = 3
=> x = 3/2
Plug in x = 3/2 , we get
f(3/2) = 2(3/2)² - 3(3/2) + 5
= 9/2 - 9/2 + 5
= 5
Therefore, remainder is 5.
Hope it helps!
Answer:
( 2x - 3 ) do not divide the polynomial directly.
Step-by-step explanation:
Since 2x - 3 = 2x - ( - 3 ), by remainder theorem :
Remainder = f( 3 / 2 )
Given, f( x ) = 2x^2 - 3x + 5
So,
= > f( 3 / 2 ) = 2( 3 / 2 )^2 - 3( 3 / 2 ) + 5
= > f( - 3 / 2 ) = 2( 9 / 4 ) - 3( 3 / 2 ) + 5
= > f( - 3 / 2 ) = 9 / 2 - 9 / 2 + 5
= > f( - 3 / 2 ) = 5
As the remainder is not 0, ( 2x - 3 ) do not divide the polynomial directly.