Question

Please help this please................

Answer 1

Answer:

It wont divide the polynomial

Step-by-step explanation:

Given, f(x) = 2x² - 3x + 5, g(x) = 2x - 3.

Long Division Method:

2x - 3) 2x² - 3x + 5 (x

           2x² - 3x

           ----------------

                           5.

Therefore, remainder is 5.

Remainder Theorem:

it states that if you divide a polynomial f(x) by (x - h) then remainder is f(h).

=> 2x - 3 = 0

=> 2x = 3

=> x = 3/2

Plug in x = 3/2 , we get

f(3/2) = 2(3/2)² - 3(3/2) + 5

         = 9/2 - 9/2 + 5

         = 5

Therefore, remainder is 5.

Hope it helps!

Answer 2

Answer:

( 2x - 3 ) do not divide the polynomial directly.

Step-by-step explanation:

Since 2x - 3 = 2x - ( - 3 ), by remainder theorem :

Remainder = f( 3 / 2 )

Given, f( x ) = 2x^2 - 3x + 5

So,

= >  f( 3 / 2 ) = 2( 3 / 2 )^2 - 3( 3 / 2 ) + 5

= >  f( - 3 / 2 ) = 2( 9 / 4 ) - 3( 3 / 2 ) + 5

= >  f( - 3 / 2 ) = 9 / 2 - 9 / 2 + 5

= >  f( - 3 / 2 ) = 5

As the remainder is not 0, ( 2x - 3 ) do not divide the polynomial directly.