Question

Construct triangle DEF such that DE=4.2cm angle D=60° angle=70° and draw circumcirlce of it​

Answer 1

Step-by-step explanation:

Let the centre of the circle be O.

AB = 12 cm

OC = 12 cm

OC ⊥ AB

We know perpendicular drawn from the centre of the circle to the chord, bisects the chord.

So, AC = 6 cm

In ⃤ OCA,

OC²+AC²=AO²⇒8²+6²=AO²⇒AO²=100⇒AO=10

Thus, AO = 10 cm

Diameter = 2 × 10 cm = 20 cm.

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Answer 2

Given : DE = 4.2 cm , angle D = 60 , angle E = 70

To Find :construct ∆DEF

draw its circumcircle .

Solution:

Step.1 : Draw a line segment DE =.4.2 cm

Step 2 : Draw an angle of 60 deg at D on DE using protractor.

Step 3 : Draw an angle of 70 deg at E on DE using protractor.

Step 4 : Both drawn angles intersects at F.

Step 5 , Draw perpendicular bisector of DF and EF which intersects at O.

Step 6 : Using compass width OD draw circle.

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Construct triangle DEF such that DE=4.2cm angle D=60° angle=70° and draw circumcirlce of it​

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