Question

container has 16 balls, out of which 3 are red balls, 6 are white balls and remaining are black balls. If a
hall is taken out without looking into the container.
i) what is the probability of getting a red ball?
ii) what is the probability of getting a black ball?​

Answer 1

Total no. of outcomes=16

No. of red balls=3

No. of white balls=6

No. of black balls=16-(6+3) = 7

Therefore,

(i) P(R) =

$\frac{3}{16}$

(ii) P(B) =

$\frac{7}{16}$

Answer 2

Answer:

Total balls = 16

Red balls = 3

White balls = 6

Black balls = 16 - 3 - 6 = 7

(i) Probability = Events occurring/Sample space

Probability (R) = 3/16

(ii) Probability (B) = 7/16

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