Question

➡CONTENT QUALITY NEEDED⬅

It is a question from class11 trigonometry

↘↘THE SUM OF TWO ANGLES IS 80 GRADES. THEIR DIFFERENCE IS 18 GRADES .FIND THE ANGLES IN DEGREES.

( NOTE THAT THE ANGLES ARE GIVEN IN GRADES NOT DEGREES)


PLS SOLVE AS SOON AS POSSIBLE
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Answer 1

Since they are complementary, then the sum of these two angles should be 90 degree. If you assume one of the angles to be x degree, then the other one is (90 - x) degree. 

 

We are also given that the difference is 18 degree, which implies that 

 

x - (90 - x) = 18

 

Now you should be able to finish the rest. 

Answer 2

We know that 1 grade = 0.9 degrees.

Then 80 grades = 0.9 * 80

                            = 72 degrees.


Then 18 grades = 0.9 * 18

                           = 16.2 degrees.


Now,

Let the two angle be x and y.

Given that sum of two angles is 80 grades

= > x + y = 72   ----- (1)

Given that Their difference is 18 grades.

= > x - y = 16.2  ---- (2)

On solving (1) & (2), we get

x + y = 72

x - y = 16.2

-----------------

2x = 88.2

x = 44.1.


Substitute x = 44.1 in (1), we get

= > x + y = 72

= > 44.1 + y = 72

= > y = 27.9.


We know that sum of angles = 180.

= > x + y + z = 180

= > 44.1 + 27.9 + z = 180

= > z = 180 - 72

= > z = 108.


Therefore the angles are 44.1, 27.9,108.(Degrees)


Hope this helps!