Math, asked by thakursspingh, 11 months ago

contract a sq whose one diagonal is 6.2 cm​

Answers

Answered by deepaksinghavdhesh
0

Step-by-step explanation:

Steps : 1. Draw BD = 6.2 cm. 2. Draw perpendicular bisector XY of BD. 3. Cut OA = OC = 3.1 cm (half the diagonal) 4. Join AB, AD, BC and CD. Thus ABCD is the required square

Answered by MediocreMin
1

Answer:

Hey mate !

Diagonal of square = √2 a

6.2 = √2 a

a = 6.2/√2 =4.384 cm

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