Contruct a rectangle ABCD such that AB=4cm and<BAC=60°
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first draw AB=4cm then draw angle of 60° from B.Then make a perpendicular from A to the line starting from B and at an angel 60° to AB(the one which you drew from B) to meet it at C.Now,drop another perpendicular at B.Then from C draw a perpendicular to join the line drawn previously from B to get point D....hence you get your required rectangle.
Ayusha765:
par kaise?
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hey friend!!!!!
step for construction
◆ draw a line AB of 4cm
◆ taking A is centre make 60°(diagonal) and a perpendicular(rectangle have its angle as 90°)
◆ mark the intersection as D
◆ now repeat the same with B
◆ mark the intersection as C
◆ join all the points and u will get ur required rectangle.....
hope it helps
plz don't forget to mark brainliest
step for construction
◆ draw a line AB of 4cm
◆ taking A is centre make 60°(diagonal) and a perpendicular(rectangle have its angle as 90°)
◆ mark the intersection as D
◆ now repeat the same with B
◆ mark the intersection as C
◆ join all the points and u will get ur required rectangle.....
hope it helps
plz don't forget to mark brainliest
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