Convert 10 newton into 10^6 dyne using dimensional analysis
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Answer:
Explanation:
the dimensional formula of Force F=[M^ 1 L^ 1 T^ −2 ]
So a=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M1 =1kg
L 1 =1m
T1 =1s
M2 =1g
L2 =1cm
T2 =1s
n1 =1Newton
n2 =?
Using the formula
n2 = n1 [M1/M2]^ a [L1/L2] ^b [T1/T2]^ c
n2 = 1 [1kg/1g]^ 1 [1m/1cm]^ 1 [1s/1s]^ −2
n2 = 1 [1000g/1g]^ 1 [100cm/1cm]^ 1×1
n2 = 1000×100
=100000
=10^5 dynes
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