Question

Convert 90 gram BaCO3 to mole

Answer 1

Answer:

Weight given of BaCO3 = 90g

Molecular mass of BaCO3 = 197g

( Atomic mass of Ba = 137g , C = 12g and O = 16g

So, Atomic mass can be find out = 137+12+(16×3) = 197g )

Moles = weight/ Molecular mass

= 90/197 = 0.457 moles

Answer 2

Answer:

90g BaCO₃ is equivalent to 0.456 moles of BaCO₃

Explanation:

Given,

   mass of BaCO₃ = 90g

Atomic mass of Ba = 137u

Atomic mass of C = 12 u

Atomic mass of O = 16u

   molar mass of BaCO₃ = 137+12+3×16

⇒                                  =  197g/mol.

number of moles =  given mass / molar mass

   moles of BaCO₃ = 90g / 197gmol⁻¹

⇒                             = 0.456 moles

Hence, the required answer is 0.456 moles