Question

correct = BRAINLIEST Given that the events A and B are such that P(A) = 1/2, P (A ∪ B) = 3/5, and P(B) = p. Find p if they are mutually exclusive.

Answer 1

Answer:

p = 1/10

Step-by-step explanation:

Hii mate ^_^

Given, P(A) = 1/2

P (A ∪ B) = 3/5

and P(B) = p

Given that, the sets A and B are mutually exclusive.

Thus, they do not have any common elements

Therefore, P(A ∩ B) = 0

We know that P(A ∪ B) = P(A) + P(B) – P(A ∩ B)

Substitute the formulas in the above-given formula, we get

3/5 = (1/2) + p – 0

Simplify the expression, we get

(3/5) – (1/2) = p

(6 − 5)/10 = p

1/10 = p

Therefore, p = 1/10

Hence,

The value of p is 1/10 , if they are mutually exclusive.

HOPE IT HELPS,

PLEASE THANK , FOLLOW AND MARK AS BRAINLIEST.

Answer 2

Answer:

1/10

Step-by-step explanation: