Question

cos=12/13 find sintheta

Answer 1

heya friends. ⬇

Here is ur answer ...
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cos¢=12/23. 【given】

【let us assume that p' is perpendicular,b is base and h' is height of a right angled triangle】

then....
.cos¢=b/h=12/13.

now...by using Pythagoras theorm...

p=√h^2-b^2

=>√169-144

=>√25

p=5 .....1]

sin¢=p/h..=5/13...from 1)....

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hope it help you...

@Rajukumar1☺☺

Answer 2

costheta =adjustant side /hypotenuse
=12/13
In triangle by P.T,
13sq.=12sq+opp.side sq.
=169-144=opposite side sq.
=25
=5
sin theta =5/13.