Math, asked by Navned, 1 year ago

cos 60cos45 -sin 60 sin 45

Answers

Answered by Nandhu1011
3
cos60.cos45 - sin 60 sin 45
=√3/2.1/√2 -√3/2.1/√2
=0
Answered by Anonymous
1
cos 60°.cos 45° - sin 60°.sin 45°
Given cos 60° = 1/2, cos 45° = 1/√2, sin 60° = √3/2, sin 45° = 1/√2
1/2 * 1/√2 - √3/2 * 1/√2
1/2√2 - √3/2√2
1 - √3
    2√2
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