cos 64 degree into cos 26 degree minus sin 64 degree into sin 26 degree
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Using cos(90-a)=Sina
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as we know cosAcosB-sinAsinB=cos(A+B)
so it will be cos(64°+26°)=cos90°=0
so it will be cos(64°+26°)=cos90°=0
kartikkagra:
ok
tan35*tan40*tan*45*tan50*tan55=
can you solve it
i have solved it the answer is 1.
tell me how to solve
(tan35tan55)(tan40tan50)tan45=(tan35cot35)(tan40cot40)tan45=1
thanks
wlcm
If ABCD is a trapezium, AC and BD are the diagonals intersecting each other at point o. Then AC:BD=
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