Question

cos 90+theta - sin 50 - theta + cos²40+cos²50 by sin²40+sin²50​

Answer 1

cos(40 - θ) - sin(50 + θ) + {cos²40° + cos²50°}/{sin²40° + sin²50°}

we know , sin(90° - x) = cos x and cos(90° - x) = sin x.

so, sin(50+ θ) = sin{90° -(40° - θ)} = cos(40° -θ)----(1)

cos 40° = cos(90° - 50°) = sin 50° ----(2)

from equations (1) and (2),

= cos(40° - θ) - cos(40° - θ) + (sin²50° + cos²50°)/(sin²40° + cos²40°)

[ sin²50° + cos²50° = 1 and sin²40° + cos²40° = 1]

= 0 + 1/1 = 1 [ans]

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Answer 2

Answer:

I hope answer is helpful to us