cos(A+B)=1 sin(A-B)= 1/2root find A, B
Answers
Answered by
2
Hello !!
Cos0° = 1
And,
Sin45° = 1/✓2
Cos ( A + B ) = 1
Cos ( A + B ) = Cos0
A + B = 0 ----------(1)
And,
Sin ( A - B ) = 1/✓2
Sin ( A - B ) = Sin45
A - B = 45 --------(2)
From equation (1) we get,
A + B = 0
A = (- B )
Putting the value of A in equation (2)
A - B = 45
-B - B = 45
-2B = 45
B = - 45/2
Putting the value of B in equation (3)
A = -B = -(-45/2) = 45/2
Hence,
A = 45/2 and B = -45/2 .
Cos0° = 1
And,
Sin45° = 1/✓2
Cos ( A + B ) = 1
Cos ( A + B ) = Cos0
A + B = 0 ----------(1)
And,
Sin ( A - B ) = 1/✓2
Sin ( A - B ) = Sin45
A - B = 45 --------(2)
From equation (1) we get,
A + B = 0
A = (- B )
Putting the value of A in equation (2)
A - B = 45
-B - B = 45
-2B = 45
B = - 45/2
Putting the value of B in equation (3)
A = -B = -(-45/2) = 45/2
Hence,
A = 45/2 and B = -45/2 .
Answered by
3
Here is your answer
a+b=0__(1)
a-b=45__(2)
subtract eq(1) and eq(2)
-2b=45
b=-45/2
and
a = 45/2.
Hope it helps you ^_^
a+b=0__(1)
a-b=45__(2)
subtract eq(1) and eq(2)
-2b=45
b=-45/2
and
a = 45/2.
Hope it helps you ^_^
Similar questions