Cos A minus Sin A + 1 by Cos A + Cos A minus 1 equal to 1 + cos theta by sin a
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Answer:
Step-by-step explanation:
LHS = (cos∅ - sin∅ + 1)/(cos∅ + sin∅-1)
dividing sin∅ both Numerator and denominator.
= (cos∅/sin∅ - sin∅/sin∅ + 1/sin∅)/(cos∅/sin∅ + sin∅/sin∅ - 1/sin∅)
= (cot∅ - 1 + cosec∅)/(cot∅ + 1 - cosec∅)
now, put 1 = cosec²∅ - cot²∅ in numerator
= {cot∅ + cosec∅ - (cosec²∅-cot²∅)}/(cot∅-cosec∅ +1)
= (cosec∅+cot∅)(1 - cosec∅ + cot∅)/(cot∅-cosec∅+1)
= cosec∅ + cot∅ = RHS
LHS = RHS
Hence proved.
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