cos inverse(cos7π/6)=?
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Answered by
16
Answer:
=
5π÷6. least value
Explaination:
cos^-1(cos(7pi/6))=cos^-1(cos(pi+pi/6))=cos^-1(-cos(pi/6))=cos^-1(cos(pi-pi/6))=cos^-1(cos(5pi/6))=5pi/6
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