cos(sin(cos(sin(45π-x))) min value
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cos(sin(cos(sinx)))
[as 45π is multiple of π and sign is positive due to sin is positive in 2nd quadtrant]
for min value sin(cos(sin))=-1
sin(cos(sinx)=sin(-π/2)
cos(sinx)=-π/2
not solved further
Cos is outer function And its MIN VALUE US -1 so simple
[as 45π is multiple of π and sign is positive due to sin is positive in 2nd quadtrant]
for min value sin(cos(sin))=-1
sin(cos(sinx)=sin(-π/2)
cos(sinx)=-π/2
not solved further
Cos is outer function And its MIN VALUE US -1 so simple
bhanu1234:
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