Cos teete/1+sin teeta + 1+ sin teeta / cos teeta =2 sec teeta
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Answer:
(1+cotθ−cosecθ)(1+tanθ+secθ)=(1+cosθsinθ−1sinθ)(1+sinθcosθ+1cosθ)
=(sinθ+cosθ−1sinθ)(sinθ+cosθ+1cosθ)
=(sinθ+cosθ)2−12sinθcosθ
=sin2θ+cos2θ+2sinθcosθ−1sinθcosθ
=1+2sinθcosθ−1sinθcosθ
=2sinθcosθsinθcosθ
=2
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