Question

Cos teete/1+sin teeta + 1+ sin teeta / cos teeta =2 sec teeta

Answer 1

Answer:

(1+cotθ−cosecθ)(1+tanθ+secθ)=(1+cosθsinθ−1sinθ)(1+sinθcosθ+1cosθ)

=(sinθ+cosθ−1sinθ)(sinθ+cosθ+1cosθ)

=(sinθ+cosθ)2−12sinθcosθ

=sin2θ+cos2θ+2sinθcosθ−1sinθcosθ

=1+2sinθcosθ−1sinθcosθ

=2sinθcosθsinθcosθ

=2