Question

cos theta + sin theta equals to root 2

Answer 1

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Answer 2

Hey here is your answer
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$( \cos(o) + \sin(o) ) = \sqrt{2} \\ \\ {( \cos(o) + \sin(o) )}^{2} = {( \sqrt{2} )}^{2} \\ \: \: \: \: \: \: \: \: \: ...... \: \: \: sq. \: both \: side \\ \\ { \cos(o) }^{2} + { \sin(o) }^{2} + 2 \sin(o) \cos(o) = 2 \\ \\ 1 + 2\sin(o) \cos(o) = 2 \\ \\ 2\sin(o) \cos(o) = 2 - 1 \\ \\ \sin(o) \cos(o) = \frac{1}{2}$
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