cos x + sec x =2 find cos^10 (x) + sec^20 (x)
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cosx+1/cosx =2
cos²x -2cosx +1 =0
let cosx =t
t²-2t+1=0
t(t-1)-1(t-1)=0
(t-1)(t-1)=0
then t=1,1
then cosx = 1
1/secx =1 then secx =1
then cos^10(x)+sec^20(x)= 1^10+1^20=1+1=2
cos²x -2cosx +1 =0
let cosx =t
t²-2t+1=0
t(t-1)-1(t-1)=0
(t-1)(t-1)=0
then t=1,1
then cosx = 1
1/secx =1 then secx =1
then cos^10(x)+sec^20(x)= 1^10+1^20=1+1=2
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