∫cos2xdx = what
limits are are x to 0.
please answer......
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cos2x=cos^x-sin^2x
Lim cos^2x-Lim sin^2x
x->0. x->0
1-0=1
Lim cos^2x-Lim sin^2x
x->0. x->0
1-0=1
dosti05:
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