Math, asked by 20012m019, 6 days ago

`cos3x+8cos^(3)x=0`??

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Answered by soumaryasoumalya12

2

Answer:

To prove:cos3x+8cos3x=0LHS=cos3x+8cos3x=4cos3x−3cosx+8cos3x [∵cos3A=4cos3A−3cosA]=12cos3x−3cosx=3cosx(4cos2x−1)Please recheck your question because we cannot get the desired result.To prove:cos3x+8cos3x=0LHS=cos3x+8cos3x=4cos3x-3cosx+8cos3x ∵cos3A=4cos3A-3cosA=12cos3x-3cosx=3cosx4cos2x-1Please recheck your question because we cannot get the desired result.

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