cosA /1- tana + sinA/1-cot A = sinA + cosA
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Answered by
0
Answer:
Here is the solution -
= (sinA + 1 - COSA) / (COSA - 1 + sinA)
Divide each term by cosA
=(tanA + secA 1)/ (1 - secA + tanA)
=[tanA + secA - ( sec? A - tanA)] /
(1- secA + tanA)
= (tanA+seCA)(1 - secA + tanA )/(1 secA + tanA)
= tanA + secA
= (sinA / cosA )+ 1/ cosA
=
(sinA +1)/ cosA
Hence Proved
Hope it will help you
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1
Answer:
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