cosA+sinA= √2, then what is sin2A?
Answers
Answered by
3
Hi...☺
Here is your answer...✌
Given that,
cosA+sinA = √2
Squaring both sides
we get ,
(cosA+sinA)² = (√2)²
cos²A+sin²A+2sinA cosA = 2
1+sin2A = 2
sin2A = 1
{ using, cos²A+sin²A = 1
and 2sinA cosA = sin2A }
Here is your answer...✌
Given that,
cosA+sinA = √2
Squaring both sides
we get ,
(cosA+sinA)² = (√2)²
cos²A+sin²A+2sinA cosA = 2
1+sin2A = 2
sin2A = 1
{ using, cos²A+sin²A = 1
and 2sinA cosA = sin2A }
chin2benup6quoo:
Thank Bro
Answered by
0
Take A=45
Den put value so Sin2A=Sin2*45= Sin 90
Sin90= 1
Den put value so Sin2A=Sin2*45= Sin 90
Sin90= 1
Similar questions