Question

cosec^2 60 . sec^2 30 . cos0 . sin45 . cot^2 60 . tan^2 60

Answer 1

Answer:

$=\frac{16}{9\sqrt{2} } or\frac{8\sqrt{2} }{9}$

Step-by-step explanation:

$cosec^{2}60 *sec^{2}30*cos0*sin45*cot^{2}60*tan^{2}60$

$=(\frac{2}{\sqrt{3} } )^{2} *(\frac{2}{\sqrt{3} } )^{2}*1*\frac{1}{\sqrt{2} } *(\frac{1}{\sqrt{3} } )^{2}*(\sqrt{3} )^{2}$

$= \frac{4}{3} *\frac{4}{3} *1*\frac{1}{\sqrt{2} } *\frac{1}{3} *3$

$=\frac{48}{27\sqrt{2} }$  ⇒ $\frac{16}{9\sqrt{2} }$    [∵ on cancellation]

$=\frac{16}{9\sqrt{2} }*\frac{9\sqrt{2} }{9\sqrt{2}}$   [∵ on rationalizing the denominator]

$= \frac{8\sqrt{2} }{9}$

I HOPE THIS HELPED YOU. PLZZ MARK THIS ANSWER AS BRAINLIEST.