Question

cosec 90-a .sin 180-A.cot 360-A/sec 180+A.tan 90+A.sin(-A)=1

Answer 1

Solution:

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i) cosec(90-A) = secA

ii)sin(180-A) = sinA

iii) cot(360-A) = -cotA

iv)sec(180+A) = -secA

v)tan(90+A) = -cotA

vi) sin(-A) = -sinA

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Now,

LHS=cosec 90-a .sin 180-A.cot 360-A/sec 180+A.tan 90+A.sin(-A)

=[secA*sinA*(-cotA)]/[(-secA*(-cotA)*(-sinA)]

After cancellation, we get

= 1

= RHS

••••

Answer 2

Answer:

Step-by-step explanation: