Question

Cosec square theta + sec square theta by cosec square theta minus sec square theta is equal to 1 + tan square
theta by 1 minus tan square theta

Answer 1

To Prove:

$\dfrac{ { \cosec{}^{2} + \sec }^{2} }{\cosec{}^{2} - { \sec }^{2}} = \dfrac{1 + { \tan}^{2} }{1 - { \tan}^{2}}$

How to solve ?

This question is based on Trigonometry Rules.

1. You have knowledge of Trigonometry.

2. By Using Trigonometry Rules you have to Simplify.

Solution:

See in the Attachment.

Answer 2

Answer:

1st answer boht OP hai