Math, asked by sanviXIV, 1 year ago

(cosec theta - cot theta)^2 = 1-cos theta/1+cos theta​

Answers

Answered by ravi9848267328
5

Answer:

Step-by-step explanation:

(cotθ-cosecθ)²

=cot²θ-2cotθcosecθ+cosec²θ

=cos²θ/sin²θ-2(cosθ/sinθ)(1/sinθ)+1/sin²θ

=cos²θ/sin²θ-2cosθ/sin²θ+1/sin²θ

=(cos²θ-2cosθ+1)/sin²θ

=(1-cosθ)²/(1-cos²θ)

=(1-cosθ)²/(1+cosθ)(1-cosθ)

=(1-cosθ)/(1+cosθ)


sanviXIV: not cot yheta -cosec theta
ravi9848267328: i will edit
sanviXIV: hmm
ravi9848267328: hey i wont becoz u will get same answer
sanviXIV: yeah its alright
ravi9848267328: : )
sanviXIV: :)
ravi9848267328: which class question
sanviXIV: 10 th
ravi9848267328: ok
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