Math, asked by nihal6666, 10 months ago

(CosecA-sinA)(secA-cosA)sec²A =tanA

Answers

Answered by vanshtyagi225

2

Answer:

(cosecA-sinA)(secA-cosA)sec^2A=tanA

Step-by-step explanation:

L.H.S

(1/sinA-sinA)(1/cosA-cosA)sec^2A

(1-sin^2A/sinA)(1-cos^2A/cosA)sec^2A

(cos^2A/sinA)(sin^2A/cosA)sec^2A

cosA*sinA*sec^2A

we write cosA=1/secA

1/secA*sinA*sec^2A

sinA*secA

we write secA=1/cosA

sinA/cosA=tanA

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