Question

cosecc48+tan88 in ratios of angles between 0°and 45°

Answer 1

As cosecФ = sec(90-Ф)
and tanβ = cot(90-β)
So,
cosec(48) = sec(90-48) = sec(42)
Similarly,
tan(88) = cot(90-88) = cot(2)
Thus,
cosec(48) + tan(2) = sec(42) + cot(2)
Hope this helps.

Answer 2

hope it's help you. :)