Math, asked by TheAishtonsageAlvie, 1 year ago

cosecc48+tan88 in ratios of angles between 0°and 45°

Answers

Answered by kanha1verma
5
As cosecФ = sec(90-Ф)
and tanβ = cot(90-β)
So,
cosec(48) = sec(90-48) = sec(42)
Similarly,
tan(88) = cot(90-88) = cot(2)
Thus,
cosec(48) + tan(2) = sec(42) + cot(2)
Hope this helps.

Answered by bhaskarnatvar3313
6
hope it's help you. :)
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bhaskarnatvar3313: thanks
TheAishtonsageAlvie: hmm
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bhaskarnatvar3313: patna
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