Question

cot^2 theta -1/sin^2 theta =-1​

Answer 1

Answer:

2cot2θ=(1+cotθ)2 

sin2θ2cos2θ=sin2θ(sinθ+cosθ)2

2sin2θcos2θ4cos22θ=sin2θ1+sin2θ

sinθ2(1+cosθ)=sin2θ1+sin2θ

⇒2sin2θ−sinθ=0

⇒sinθ(2sinθ−1)=0

⇒sinθ=0orsinθ=21

The general solution are θ=mπ,m∈z , θ=nπ+(−1)

Step-by-step explanation:

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