Question

CotA+cotB+cotC=√3 prove triangle ABC equlateral triangle

Answer 1

In an equilateral triangle
A=B=C
so
A+B+C= λ
A=B=C= λ/3

Therefore,

cot A + cot B + cot C = cot λ/3 + cot λ/3 + cot λ/3 

= 1/√3 + 1/√3 + 1/√3

= 3/√3

= √3