Cr2O7(-2) +SO2=Cr+3+SO4(-2)(Acidic )
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The reaction we are given here to Balance gives cr_{3}+ +  is basically an example or a type of redox reaction.
In other words we can say there are two types of half reactions that has been taking place in the above given reaction one that has oxidation happening in it and other half has reduction happening in it.
So the two reactions to balance the equation would be


Show the final balanced equation will be

To know more:
Cr2O7 2-+ SO3 2-GIVES RISE TO Cr 3+ SO4 2- BALANCE BY OXIDATION NUMBER METHOD
brainly.in/question/1060762
Balance the following redox reactions by ion-electron method:
(a) MnO4(-) (aq) + I– (aq)→MnO2 (s) + I2(s) (in basic medium)
(b) MnO4(-) (aq) + SO2 (g)→Mn2+ (aq) + HSO4(-) (aq) (in acidic solution)
(c) H2O2 (aq) + Fe2+ (aq)→Fe3+ (aq) + H2O (l) (in acidic solution)
(d)Cr2O7(2-) + SO2(g)→Cr3+ (aq) + SO4(2-) (aq) (in acidic solution)
The reaction we are given here to Balance gives cr_{3}+ +  is basically an example or a type of redox reaction.
In other words we can say there are two types of half reactions that has been taking place in the above given reaction one that has oxidation happening in it and other half has reduction happening in it.
So the two reactions to balance the equation would be


Show the final balanced equation will be

To know more:
Cr2O7 2-+ SO3 2-GIVES RISE TO Cr 3+ SO4 2- BALANCE BY OXIDATION NUMBER METHOD
brainly.in/question/1060762
Balance the following redox reactions by ion-electron method:
(a) MnO4(-) (aq) + I– (aq)→MnO2 (s) + I2(s) (in basic medium)
(b) MnO4(-) (aq) + SO2 (g)→Mn2+ (aq) + HSO4(-) (aq) (in acidic solution)
(c) H2O2 (aq) + Fe2+ (aq)→Fe3+ (aq) + H2O (l) (in acidic solution)
(d)Cr2O7(2-) + SO2(g)→Cr3+ (aq) + SO4(2-) (aq) (in acidic solution)
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