Question

Critical angle of a medium respect to free space is 60°.what is the velocity of light in this medium?

A) 3√3/2 ×10^8 m/sec

B) 2√3 ×10^8 m/sec

C) 2/√3 ×10^8 m/sec

D) √3 /2×10^8 m/sec​

Answer 1

Explanation:

i think so D)√3 /2×10^8 m/sec

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Answer 2

Answer :

Critical angle of medium = 60°

We have to find speed of light in this medium$.$

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◈ First of all we need to find refractive index of the medium.

Relation between critical angle of medium and refractive index is given by

• η = 1 / sin C

➝ η = 1 / sin 60°

➝ η = 1 / (√3/2)

➝ η = 2/√3

◈ Refractive index of medium is defined as the ratio of speed of light in vacuum to speed of light in medium.

• η = c / v

value of c = 3×10$^8$ m/s

⇒ 2/√3 = 3×10$^8$/v

⇒ v = 3√3/2 × 10$^8$ m/s