CSA of hollow cylinder is 4224cm square. it is cut along its height and form rectangle of width 32cm. what is the perimeter of the rectangle?
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CSA= 4224 cm
l=32 cm
perimeter of rectrangle=2(l+b)
4224=2(32+b)
4224/2=32+b
2112=32+b
2112-32=b
2080=b
l=32 cm
perimeter of rectrangle=2(l+b)
4224=2(32+b)
4224/2=32+b
2112=32+b
2112-32=b
2080=b
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