Science, asked by dschouhan6599, 1 year ago

CsCl has bcc arrangement. Its unit cell edge length is 400 pm.

Answers

Answered by ashimavjo
4
CsCI has body centred cubic structure
interionic distance=√3/2 a
edge length a = 400pm
interionic distance=√3/2×400
=1.732×200
=346.4pm
Answered by rosamariabiju03
1

Answer:

*346.4pm*

Explanation:

For bcc arrangement,

inter ionic distance =√3/2a=√3/2*400=*346.4pm*

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