Question

Cu(OH)2 + N2H4 ----> Cu +N2
balance the above reaction by oxidation number method in basic medium

Answer 1

Cu+2(O-2H+1)2 + 2e- → Cu0

(Cu)

 Combine these redox couples into two half-reactions: one for the oxidation, and one for the reduction (see: Divide the redox reaction into two half-reactions).

Answer 2

$\huge\underline\mathfrak\red{Answer}$

Cu+2(O-2H+1)2 + 2e- → Cu0

(Cu)

Combine these redox couples into two half-reactions: one for the oxidation, and one for the reduction (see: Divide the redox reaction into two half-reactions).